Solution kindly provided by datr. Elaborated a bit by moi.

First let u = 1 - 3x - 2x^2.

Then du/dx = -3 - 4x

So, force the numerator into -3 - 4x, like so:

1 + 2x = -1/2(-2 - 4x) = -1/2(-3 - 4x + 1) = - 1/2(-3 - 4x) - 1/2

Hence, the integral must be split into two integrals, one relatively easy to solve by chain rule since numerator is derivative of the denominator.

First one easily solved using chain rule (or by inspection), and the second one needs a bit more working. Can change the second integral to a standard form if you complete the square and take the factor of 1/sqrt2 out.

Then just use arcsine to finish it off!

## Wednesday, May 16, 2007

Subscribe to:
Post Comments (Atom)

## No comments:

Post a Comment